w^2-9w-580=0

Solution for w^2-9w-580=0 equation:

w^2-9w-580=0

a = 1; b = -9; c = -580;
Δ = b2-4ac
Δ = -92-4·1·(-580)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-49}{2*1}=\frac{-40}{2}
=-20
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+49}{2*1}=\frac{58}{2}
=29
$